5x^2-23x-36=0

Solution for 5x^2-23x-36=0 equation:

5x^2-23x-36=0

a = 5; b = -23; c = -36;
Δ = b2-4ac
Δ = -232-4·5·(-36)
Δ = 1249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{1249}}{2*5}=\frac{23-\sqrt{1249}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{1249}}{2*5}=\frac{23+\sqrt{1249}}{10}
$